If a pendulum has a length of 1 meter, what is its period of oscillation in seconds?

The period of a simple pendulum can be calculated using the formula ( T = 2\pi \sqrt{\frac{L}{g}} ), where ( T ) is the period, ( L ) is the length of the pendulum, and ( g ) is the acceleration due to gravity, approximately ( 9.81 , m/s^2 ).

For a pendulum length of 1 meter, the calculation would be: [

T = 2\pi \sqrt{\frac{1}{9.81}}. ] Calculating this gives: [ \sqrt{\frac{1}{9.81}} \approx 0.319. ] Therefore, [ T \approx 2\pi \times 0.319 \approx 2 \times 3.14159 \times 0.319 \approx 2.0 , seconds. ]

This confirms that the period of oscillation for a 1-meter pendulum is approximately 2 seconds, making the chosen answer the correct one. Understanding the relationship between the length of the pendulum and its period is crucial, as it provides insight into harmonic motion, which can be foundational when studying oscillatory systems